{"id":6265,"date":"2015-12-21T09:06:53","date_gmt":"2015-12-21T08:06:53","guid":{"rendered":"http:\/\/penszko.blog.polityka.pl\/?p=6265"},"modified":"2015-12-21T09:06:53","modified_gmt":"2015-12-21T08:06:53","slug":"spoko","status":"publish","type":"post","link":"https:\/\/blog.polityka.pl\/penszko\/2015\/12\/21\/spoko\/","title":{"rendered":"Spoko"},"content":{"rendered":"<p>Prosz\u0119 podzieli\u0107 diagram wzd\u0142u\u017c linii przerywanych na trzy cz\u0119\u015bci o jednakowej wielko\u015bci, ale r\u00f3\u017cnym kszta\u0142cie tak, aby w ka\u017cdej cz\u0119\u015bci znalaz\u0142a si\u0119 parzysta liczba sp\u00f3\u0142g\u0142osek i nieparzysta samog\u0142osek.<\/p>\n<p><a href=\"\/wp-content\/uploads\/2015\/12\/Spo_1.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-6266\" src=\"\/wp-content\/uploads\/2015\/12\/Spo_1-300x182.jpg\" alt=\"Spo_1\" width=\"300\" height=\"182\" srcset=\"\/penszko\/wp-content\/uploads\/2015\/12\/Spo_1-300x182.jpg 300w, \/penszko\/wp-content\/uploads\/2015\/12\/Spo_1-1024x620.jpg 1024w, \/penszko\/wp-content\/uploads\/2015\/12\/Spo_1.jpg 2000w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/a><\/p>\n<p>Sposoby podzia\u0142u s\u0105 dwa. Jako rozwi\u0105zanie ko\u0144cowe wystarczy poda\u0107, ile cz\u0119\u015bci w jednym podziale ma taki sam kszta\u0142t, jak w drugim.<\/p>\n<p><a href=\"\/wp-content\/uploads\/2013\/05\/Kom.jpg\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-4770\" src=\"\/wp-content\/uploads\/2013\/05\/Kom.jpg\" alt=\"Kom\" width=\"1200\" height=\"32\" srcset=\"\/penszko\/wp-content\/uploads\/2013\/05\/Kom.jpg 1200w, \/penszko\/wp-content\/uploads\/2013\/05\/Kom-300x8.jpg 300w, \/penszko\/wp-content\/uploads\/2013\/05\/Kom-1024x27.jpg 1024w, \/penszko\/wp-content\/uploads\/2013\/05\/Kom-e1574337004355-768x20.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Prosz\u0119 podzieli\u0107 diagram wzd\u0142u\u017c linii przerywanych na trzy cz\u0119\u015bci o jednakowej wielko\u015bci, ale r\u00f3\u017cnym kszta\u0142cie tak, aby w ka\u017cdej cz\u0119\u015bci znalaz\u0142a si\u0119 parzysta liczba sp\u00f3\u0142g\u0142osek i nieparzysta samog\u0142osek. Sposoby podzia\u0142u s\u0105 dwa. Jako rozwi\u0105zanie ko\u0144cowe wystarczy poda\u0107, ile cz\u0119\u015bci w jednym podziale ma taki sam kszta\u0142t, jak w drugim.<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"_links":{"self":[{"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/posts\/6265"}],"collection":[{"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/comments?post=6265"}],"version-history":[{"count":2,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/posts\/6265\/revisions"}],"predecessor-version":[{"id":6268,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/posts\/6265\/revisions\/6268"}],"wp:attachment":[{"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/media?parent=6265"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/categories?post=6265"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/tags?post=6265"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}