{"id":6538,"date":"2016-07-22T06:03:05","date_gmt":"2016-07-22T05:03:05","guid":{"rendered":"http:\/\/penszko.blog.polityka.pl\/?p=6538"},"modified":"2016-07-22T06:03:05","modified_gmt":"2016-07-22T05:03:05","slug":"do-trzech","status":"publish","type":"post","link":"https:\/\/blog.polityka.pl\/penszko\/2016\/07\/22\/do-trzech\/","title":{"rendered":"Do trzech"},"content":{"rendered":"<p>W bie\u017c\u0105cym <em>Omnibusie<\/em> na stronie 31 s\u0105 trzy zadania pod wsp\u00f3lnym tytu\u0142em \u201ePodzielno\u015b\u0107 my\u015blenia\u201d. Ka\u017cde z nich polega na podzieleniu diagramu wzd\u0142u\u017c linii przerywanych na cz\u0119\u015bci (wielok\u0105ty) jednakowej wielko\u015bci \u2013 ka\u017cda z\u0142o\u017cona z pi\u0119ciu kratek (pentomino) \u2013 ale o <strong>r\u00f3\u017cnym<\/strong> kszta\u0142cie. W diagram wpisana jest z\u0142ota my\u015bl, a z tworz\u0105cymi j\u0105 literami wi\u0105\u017ce si\u0119 dodatkowy warunek dotycz\u0105cy podzia\u0142u.<br \/>\nDrugi diagram wygl\u0105da tak:<\/p>\n<p><a href=\"\/wp-content\/uploads\/2016\/07\/Dot.jpg\" rel=\"attachment wp-att-6539\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-medium wp-image-6539\" src=\"\/wp-content\/uploads\/2016\/07\/Dot-241x300.jpg\" alt=\"Dot\" width=\"241\" height=\"300\" srcset=\"\/penszko\/wp-content\/uploads\/2016\/07\/Dot-241x300.jpg 241w, \/penszko\/wp-content\/uploads\/2016\/07\/Dot-768x957.jpg 768w, \/penszko\/wp-content\/uploads\/2016\/07\/Dot-822x1024.jpg 822w, \/penszko\/wp-content\/uploads\/2016\/07\/Dot.jpg 2000w\" sizes=\"(max-width: 241px) 100vw, 241px\" \/><\/a><\/p>\n<p>Podzia\u0142u na cztery <strong>r\u00f3\u017cne<\/strong> pentominowe cz\u0119\u015bci nale\u017cy dokona\u0107 w taki spos\u00f3b, aby w ka\u017cdej znalaz\u0142a si\u0119 <strong>inna<\/strong> liczba sp\u00f3\u0142g\u0142osek.<br \/>\nW <em>Omnibusie<\/em> podane s\u0105 dwa rozwi\u0105zania:<br \/>\n1) <strong>N<\/strong><em>I<\/em><strong>MPM<\/strong> \u2013 <strong>J<\/strong><em>AEYO<\/em> \u2013 <strong>PWR\u015aT<\/strong> \u2013 <strong>L<\/strong><em>E<\/em><strong>W<\/strong><em>\u00d3<\/em><strong>M<\/strong><br \/>\n2) <strong>N<\/strong><em>I<\/em><strong>MPM<\/strong> \u2013 <em>AE<\/em><strong>R<\/strong><em>YO<\/em> \u2013 <strong>JPWL\u015a<\/strong> \u2013 <strong>T<\/strong><em>E<\/em><strong>W<\/strong><em>\u00d3<\/em><strong>M<\/strong><br \/>\nTymczasem kilku czytelnik\u00f3w poinformowa\u0142o mnie o trzecim rozwi\u0105zaniu. Jakim?<\/p>\n<p><a href=\"\/wp-content\/uploads\/2013\/05\/Kom.jpg\" rel=\"attachment wp-att-4770\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-4770\" src=\"\/wp-content\/uploads\/2013\/05\/Kom.jpg\" alt=\"Kom\" width=\"1200\" height=\"32\" srcset=\"\/penszko\/wp-content\/uploads\/2013\/05\/Kom.jpg 1200w, \/penszko\/wp-content\/uploads\/2013\/05\/Kom-300x8.jpg 300w, \/penszko\/wp-content\/uploads\/2013\/05\/Kom-1024x27.jpg 1024w, \/penszko\/wp-content\/uploads\/2013\/05\/Kom-e1574337004355-768x20.jpg 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>W bie\u017c\u0105cym Omnibusie na stronie 31 s\u0105 trzy zadania pod wsp\u00f3lnym tytu\u0142em \u201ePodzielno\u015b\u0107 my\u015blenia\u201d. Ka\u017cde z nich polega na podzieleniu diagramu wzd\u0142u\u017c linii przerywanych na cz\u0119\u015bci (wielok\u0105ty) jednakowej wielko\u015bci \u2013 ka\u017cda z\u0142o\u017cona z pi\u0119ciu kratek (pentomino) \u2013 ale o r\u00f3\u017cnym kszta\u0142cie. W diagram wpisana jest z\u0142ota my\u015bl, a z tworz\u0105cymi j\u0105 literami wi\u0105\u017ce si\u0119 dodatkowy [&hellip;]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"_links":{"self":[{"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/posts\/6538"}],"collection":[{"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/users\/3"}],"replies":[{"embeddable":true,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/comments?post=6538"}],"version-history":[{"count":5,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/posts\/6538\/revisions"}],"predecessor-version":[{"id":6545,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/posts\/6538\/revisions\/6545"}],"wp:attachment":[{"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/media?parent=6538"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/categories?post=6538"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/blog.polityka.pl\/penszko\/wp-json\/wp\/v2\/tags?post=6538"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}